5y-10+y+3=7y+20-4y

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Solution for 5y-10+y+3=7y+20-4y equation: 



5y-10+y+3=7y+20-4y

We move all terms to the left:

5y-10+y+3-(7y+20-4y)=0

We add all the numbers together, and all the variables

5y+y-(3y+20)-10+3=0

We add all the numbers together, and all the variables

6y-(3y+20)-7=0

We get rid of parentheses

6y-3y-20-7=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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