5y-10+y+3=7y+20-4y

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Solution for 5y-10+y+3=7y+20-4y equation:



5y-10+y+3=7y+20-4y
We move all terms to the left:
5y-10+y+3-(7y+20-4y)=0
We add all the numbers together, and all the variables
5y+y-(3y+20)-10+3=0
We add all the numbers together, and all the variables
6y-(3y+20)-7=0
We get rid of parentheses
6y-3y-20-7=0
We add all the numbers together, and all the variables
3y-27=0
We move all terms containing y to the left, all other terms to the right
3y=27
y=27/3
y=9

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