5y-10+y+48=8y+50-6y

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Solution for 5y-10+y+48=8y+50-6y equation:



5y-10+y+48=8y+50-6y
We move all terms to the left:
5y-10+y+48-(8y+50-6y)=0
We add all the numbers together, and all the variables
5y+y-(2y+50)-10+48=0
We add all the numbers together, and all the variables
6y-(2y+50)+38=0
We get rid of parentheses
6y-2y-50+38=0
We add all the numbers together, and all the variables
4y-12=0
We move all terms containing y to the left, all other terms to the right
4y=12
y=12/4
y=3

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