5y-12=-8/y

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Solution for 5y-12=-8/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5*y-12 = -8/y // + -8/y

5*y-(-8/y)-12 = 0

5*y+8*y^-1-12 = 0

5*y^1+8*y^-1-12*y^0 = 0

(5*y^2-12*y^1+8*y^0)/(y^1) = 0 // * y^2

y^1*(5*y^2-12*y^1+8*y^0) = 0

y^1

5*y^2-12*y+8 = 0

5*y^2-12*y+8 = 0

DELTA = (-12)^2-(4*5*8)

DELTA = -16

DELTA < 0

y in { } 

y belongs to the empty set

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