5y-1=2(4y-5)

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Solution for 5y-1=2(4y-5) equation: 



5y-1=2(4y-5)

We move all terms to the left:

5y-1-(2(4y-5))=0



We calculate terms in parentheses: -(2(4y-5)), so:

2(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)



We get rid of parentheses

5y-8y+10-1=0

We add all the numbers together, and all the variables

-3y+9=0

We move all terms containing y to the left, all other terms to the right

-3y=-9

y=-9/-3

y=+3

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