5y-1=3y;2y-1=0

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Solution for 5y-1=3y;2y-1=0 equation: 



5y-1=3y^2y-1=0

We move all terms to the left:

5y-1-(3y^2y-1)=0

We get rid of parentheses

-3y^2y+5y+1-1=0

We add all the numbers together, and all the variables

-3y^2y+5y=0

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