5y-2(2y-7)=2(3y-1)

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Solution for 5y-2(2y-7)=2(3y-1) equation:



5y-2(2y-7)=2(3y-1)
We move all terms to the left:
5y-2(2y-7)-(2(3y-1))=0
We multiply parentheses
5y-4y-(2(3y-1))+14=0
We calculate terms in parentheses: -(2(3y-1)), so:
2(3y-1)
We multiply parentheses
6y-2
Back to the equation:
-(6y-2)
We add all the numbers together, and all the variables
y-(6y-2)+14=0
We get rid of parentheses
y-6y+2+14=0
We add all the numbers together, and all the variables
-5y+16=0
We move all terms containing y to the left, all other terms to the right
-5y=-16
y=-16/-5
y=3+1/5

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