5y-2+y+22=6y+20-4y

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Solution for 5y-2+y+22=6y+20-4y equation: 



5y-2+y+22=6y+20-4y

We move all terms to the left:

5y-2+y+22-(6y+20-4y)=0

We add all the numbers together, and all the variables

5y+y-(2y+20)-2+22=0

We add all the numbers together, and all the variables

6y-(2y+20)+20=0

We get rid of parentheses

6y-2y-20+20=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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