5y-2+y+38=8y+40-4y

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Solution for 5y-2+y+38=8y+40-4y equation:



5y-2+y+38=8y+40-4y
We move all terms to the left:
5y-2+y+38-(8y+40-4y)=0
We add all the numbers together, and all the variables
5y+y-(4y+40)-2+38=0
We add all the numbers together, and all the variables
6y-(4y+40)+36=0
We get rid of parentheses
6y-4y-40+36=0
We add all the numbers together, and all the variables
2y-4=0
We move all terms containing y to the left, all other terms to the right
2y=4
y=4/2
y=2

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