5y-2+y+38=8y+40-4y

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Solution for 5y-2+y+38=8y+40-4y equation: 



5y-2+y+38=8y+40-4y

We move all terms to the left:

5y-2+y+38-(8y+40-4y)=0

We add all the numbers together, and all the variables

5y+y-(4y+40)-2+38=0

We add all the numbers together, and all the variables

6y-(4y+40)+36=0

We get rid of parentheses

6y-4y-40+36=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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