5y-2/7y+3=5/y

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Solution for 5y-2/7y+3=5/y equation: 



5y-2/7y+3=5/y

We move all terms to the left:

5y-2/7y+3-(5/y)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R





Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

5y-2/7y-(+5/y)+3=0

We get rid of parentheses

5y-2/7y-5/y+3=0

We calculate fractions


5y+(-2y)/7y^2+(-35y)/7y^2+3=0

We multiply all the terms by the denominator


5y*7y^2+(-2y)+(-35y)+3*7y^2=0

Wy multiply elements

35y^3+21y^2+(-2y)+(-35y)=0

We get rid of parentheses

35y^3+21y^2-2y-35y=0

We do not support eypression: y^3

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