5y-3(-2+1)=2y+6(-2)+6

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Solution for 5y-3(-2+1)=2y+6(-2)+6 equation: 



5y-3(-2+1)=2y+6(-2)+6

We move all terms to the left:

5y-3(-2+1)-(2y+6(-2)+6)=0

We add all the numbers together, and all the variables

5y-(2y+6(-2)+6)-3(-1)=0

We add all the numbers together, and all the variables

5y-(2y+6(-2)+6)+3=0



We calculate terms in parentheses: -(2y+6(-2)+6), so:

2y+6(-2)+6

determiningTheFunctionDomain
2y+6+6(-2)

We add all the numbers together, and all the variables

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

5y-2y+6+3=0

We add all the numbers together, and all the variables

3y+9=0

We move all terms containing y to the left, all other terms to the right

3y=-9

y=-9/3

y=-3

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