5y-3(-3+1)=2y+6(-3)+6

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Solution for 5y-3(-3+1)=2y+6(-3)+6 equation: 



5y-3(-3+1)=2y+6(-3)+6

We move all terms to the left:

5y-3(-3+1)-(2y+6(-3)+6)=0

We add all the numbers together, and all the variables

5y-(2y+6(-3)+6)-3(-2)=0

We add all the numbers together, and all the variables

5y-(2y+6(-3)+6)+6=0



We calculate terms in parentheses: -(2y+6(-3)+6), so:

2y+6(-3)+6

determiningTheFunctionDomain
2y+6+6(-3)

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)



We get rid of parentheses

5y-2y+12+6=0

We add all the numbers together, and all the variables

3y+18=0

We move all terms containing y to the left, all other terms to the right

3y=-18

y=-18/3

y=-6

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