5y-3(y+1)=2(y+1)-5

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Solution for 5y-3(y+1)=2(y+1)-5 equation:


Simplifying
5y + -3(y + 1) = 2(y + 1) + -5

Reorder the terms:
5y + -3(1 + y) = 2(y + 1) + -5
5y + (1 * -3 + y * -3) = 2(y + 1) + -5
5y + (-3 + -3y) = 2(y + 1) + -5

Reorder the terms:
-3 + 5y + -3y = 2(y + 1) + -5

Combine like terms: 5y + -3y = 2y
-3 + 2y = 2(y + 1) + -5

Reorder the terms:
-3 + 2y = 2(1 + y) + -5
-3 + 2y = (1 * 2 + y * 2) + -5
-3 + 2y = (2 + 2y) + -5

Reorder the terms:
-3 + 2y = 2 + -5 + 2y

Combine like terms: 2 + -5 = -3
-3 + 2y = -3 + 2y

Add '3' to each side of the equation.
-3 + 3 + 2y = -3 + 3 + 2y

Combine like terms: -3 + 3 = 0
0 + 2y = -3 + 3 + 2y
2y = -3 + 3 + 2y

Combine like terms: -3 + 3 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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