5y-3(y+1)=4y+1

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Solution for 5y-3(y+1)=4y+1 equation: 



5y-3(y+1)=4y+1

We move all terms to the left:

5y-3(y+1)-(4y+1)=0

We multiply parentheses

5y-3y-(4y+1)-3=0

We get rid of parentheses

5y-3y-4y-1-3=0

We add all the numbers together, and all the variables

-2y-4=0

We move all terms containing y to the left, all other terms to the right

-2y=4

y=4/-2

y=-2

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