5y-3+2(4y+4)=-3(y+1)

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Solution for 5y-3+2(4y+4)=-3(y+1) equation:



5y-3+2(4y+4)=-3(y+1)
We move all terms to the left:
5y-3+2(4y+4)-(-3(y+1))=0
We multiply parentheses
5y+8y-(-3(y+1))+8-3=0
We calculate terms in parentheses: -(-3(y+1)), so:
-3(y+1)
We multiply parentheses
-3y-3
Back to the equation:
-(-3y-3)
We add all the numbers together, and all the variables
13y-(-3y-3)+5=0
We get rid of parentheses
13y+3y+3+5=0
We add all the numbers together, and all the variables
16y+8=0
We move all terms containing y to the left, all other terms to the right
16y=-8
y=-8/16
y=-1/2

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