5y-3+2=4(y-12)

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Solution for 5y-3+2=4(y-12) equation: 



5y-3+2=4(y-12)

We move all terms to the left:

5y-3+2-(4(y-12))=0

We add all the numbers together, and all the variables

5y-(4(y-12))-1=0



We calculate terms in parentheses: -(4(y-12)), so:

4(y-12)

We multiply parentheses

4y-48

Back to the equation:

-(4y-48)



We get rid of parentheses

5y-4y+48-1=0

We add all the numbers together, and all the variables

y+47=0

We move all terms containing y to the left, all other terms to the right

y=-47

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