5y-3+y+43=7y+40-4y

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Solution for 5y-3+y+43=7y+40-4y equation: 



5y-3+y+43=7y+40-4y

We move all terms to the left:

5y-3+y+43-(7y+40-4y)=0

We add all the numbers together, and all the variables

5y+y-(3y+40)-3+43=0

We add all the numbers together, and all the variables

6y-(3y+40)+40=0

We get rid of parentheses

6y-3y-40+40=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0

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