5y-3=7+4(4-2)

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Solution for 5y-3=7+4(4-2) equation: 



5y-3=7+4(4-2)

We move all terms to the left:

5y-3-(7+4(4-2))=0

We add all the numbers together, and all the variables

5y-3-(7+42)=0

We add all the numbers together, and all the variables

5y-52=0

We move all terms containing y to the left, all other terms to the right

5y=52

y=52/5

y=10+2/5

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