5y-4(4-y)=y+2

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Solution for 5y-4(4-y)=y+2 equation: 



5y-4(4-y)=y+2

We move all terms to the left:

5y-4(4-y)-(y+2)=0

We add all the numbers together, and all the variables

5y-4(-1y+4)-(y+2)=0

We multiply parentheses

5y+4y-(y+2)-16=0

We get rid of parentheses

5y+4y-y-2-16=0

We add all the numbers together, and all the variables

8y-18=0

We move all terms containing y to the left, all other terms to the right

8y=18

y=18/8

y=2+1/4

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