5y-4(y-2)+2=7

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Solution for 5y-4(y-2)+2=7 equation: 



5y-4(y-2)+2=7

We move all terms to the left:

5y-4(y-2)+2-(7)=0

We add all the numbers together, and all the variables

5y-4(y-2)-5=0

We multiply parentheses

5y-4y+8-5=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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