5y-4+y+32=8y+40-6y

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Solution for 5y-4+y+32=8y+40-6y equation: 



5y-4+y+32=8y+40-6y

We move all terms to the left:

5y-4+y+32-(8y+40-6y)=0

We add all the numbers together, and all the variables

5y+y-(2y+40)-4+32=0

We add all the numbers together, and all the variables

6y-(2y+40)+28=0

We get rid of parentheses

6y-2y-40+28=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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