5y-4/y-9

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Solution for 5y-4/y-9 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5*y-(4/y)-9 = 0

5*y-4*y^-1-9 = 0

5*y^1-4*y^-1-9*y^0 = 0

(5*y^2-9*y^1-4*y^0)/(y^1) = 0 // * y^2

y^1*(5*y^2-9*y^1-4*y^0) = 0

y^1

5*y^2-9*y-4 = 0

5*y^2-9*y-4 = 0

DELTA = (-9)^2-(-4*4*5)

DELTA = 161

DELTA > 0

y = (161^(1/2)+9)/(2*5) or y = (9-161^(1/2))/(2*5)

y = (161^(1/2)+9)/10 or y = (9-161^(1/2))/10

y in { (9-161^(1/2))/10, (161^(1/2)+9)/10} 

y in { (9-161^(1/2))/10, (161^(1/2)+9)/10 }

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