5y-4=7+4y-12

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Solution for 5y-4=7+4y-12 equation: 



5y-4=7+4y-12

We move all terms to the left:

5y-4-(7+4y-12)=0

We add all the numbers together, and all the variables

5y-(4y-5)-4=0

We get rid of parentheses

5y-4y+5-4=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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