5y-5(1+y)=4(y-2)-11

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Solution for 5y-5(1+y)=4(y-2)-11 equation: 



5y-5(1+y)=4(y-2)-11

We move all terms to the left:

5y-5(1+y)-(4(y-2)-11)=0

We add all the numbers together, and all the variables

5y-5(y+1)-(4(y-2)-11)=0

We multiply parentheses

5y-5y-(4(y-2)-11)-5=0



We calculate terms in parentheses: -(4(y-2)-11), so:

4(y-2)-11

We multiply parentheses

4y-8-11

We add all the numbers together, and all the variables

4y-19

Back to the equation:

-(4y-19)



We add all the numbers together, and all the variables

-(4y-19)-5=0

We get rid of parentheses

-4y+19-5=0

We add all the numbers together, and all the variables

-4y+14=0

We move all terms containing y to the left, all other terms to the right

-4y=-14

y=-14/-4

y=3+1/2

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