5y-5+4(2y+2)=-3(y+5)

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Solution for 5y-5+4(2y+2)=-3(y+5) equation: 



5y-5+4(2y+2)=-3(y+5)

We move all terms to the left:

5y-5+4(2y+2)-(-3(y+5))=0

We multiply parentheses

5y+8y-(-3(y+5))+8-5=0



We calculate terms in parentheses: -(-3(y+5)), so:

-3(y+5)

We multiply parentheses

-3y-15

Back to the equation:

-(-3y-15)



We add all the numbers together, and all the variables

13y-(-3y-15)+3=0

We get rid of parentheses

13y+3y+15+3=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8

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