5y-7/2y=3

Solution for 5y-7/2y=3 equation:

5y-7/2y=3

We move all terms to the left:

5y-7/2y-(3)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R


We multiply all the terms by the denominator


5y*2y-3*2y-7=0

Wy multiply elements

10y^2-6y-7=0

a = 10; b = -6; c = -7;
Δ = b2-4ac
Δ = -62-4·10·(-7)
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{79}}{2*10}=\frac{6-2\sqrt{79}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{79}}{2*10}=\frac{6+2\sqrt{79}}{20}
$