5y-7/3y=2

Solution for 5y-7/3y=2 equation:

5y-7/3y=2

We move all terms to the left:

5y-7/3y-(2)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We multiply all the terms by the denominator


5y*3y-2*3y-7=0

Wy multiply elements

15y^2-6y-7=0

a = 15; b = -6; c = -7;
Δ = b2-4ac
Δ = -62-4·15·(-7)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{114}}{2*15}=\frac{6-2\sqrt{114}}{30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{114}}{2*15}=\frac{6+2\sqrt{114}}{30}
$