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5y^2+5y-10=0
a = 5; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·5·(-10)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-15}{2*5}=\frac{-20}{10} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+15}{2*5}=\frac{10}{10} =1 $
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