5y2+9y=3

Solution for 5y2+9y=3 equation:

5y^2+9y=3

We move all terms to the left:

5y^2+9y-(3)=0

a = 5; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·5·(-3)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{141}}{2*5}=\frac{-9-\sqrt{141}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{141}}{2*5}=\frac{-9+\sqrt{141}}{10}
$