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5y^2-22y+24=0
a = 5; b = -22; c = +24;
Δ = b2-4ac
Δ = -222-4·5·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2}{2*5}=\frac{20}{10} =2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2}{2*5}=\frac{24}{10} =2+2/5 $
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