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5y^2-8y-13=0
a = 5; b = -8; c = -13;
Δ = b2-4ac
Δ = -82-4·5·(-13)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-18}{2*5}=\frac{-10}{10} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+18}{2*5}=\frac{26}{10} =2+3/5 $
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