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5y^2=16+2y
We move all terms to the left:
5y^2-(16+2y)=0
We add all the numbers together, and all the variables
5y^2-(2y+16)=0
We get rid of parentheses
5y^2-2y-16=0
a = 5; b = -2; c = -16;
Δ = b2-4ac
Δ = -22-4·5·(-16)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*5}=\frac{-16}{10} =-1+3/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*5}=\frac{20}{10} =2 $
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