5y=(2y+33)

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Solution for 5y=(2y+33) equation: 



5y=(2y+33)

We move all terms to the left:

5y-((2y+33))=0



We calculate terms in parentheses: -((2y+33)), so:

(2y+33)

We get rid of parentheses

2y+33

Back to the equation:

-(2y+33)



We get rid of parentheses

5y-2y-33=0

We add all the numbers together, and all the variables

3y-33=0

We move all terms containing y to the left, all other terms to the right

3y=33

y=33/3

y=11

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