5y=13+2(4y-2)

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Solution for 5y=13+2(4y-2) equation: 



5y=13+2(4y-2)

We move all terms to the left:

5y-(13+2(4y-2))=0



We calculate terms in parentheses: -(13+2(4y-2)), so:

13+2(4y-2)

determiningTheFunctionDomain
2(4y-2)+13

We multiply parentheses

8y-4+13

We add all the numbers together, and all the variables

8y+9

Back to the equation:

-(8y+9)



We get rid of parentheses

5y-8y-9=0

We add all the numbers together, and all the variables

-3y-9=0

We move all terms containing y to the left, all other terms to the right

-3y=9

y=9/-3

y=-3

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