5y=6(3-y)=4y-7

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Solution for 5y=6(3-y)=4y-7 equation: 



5y=6(3-y)=4y-7

We move all terms to the left:

5y-(6(3-y))=0

We add all the numbers together, and all the variables

5y-(6(-1y+3))=0



We calculate terms in parentheses: -(6(-1y+3)), so:

6(-1y+3)

We multiply parentheses

-6y+18

Back to the equation:

-(-6y+18)



We get rid of parentheses

5y+6y-18=0

We add all the numbers together, and all the variables

11y-18=0

We move all terms containing y to the left, all other terms to the right

11y=18

y=18/11

y=1+7/11

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