5z+1/4z-20=2*(z+4z)-1

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Solution for 5z+1/4z-20=2*(z+4z)-1 equation: 



5z+1/4z-20=2(z+4z)-1

We move all terms to the left:

5z+1/4z-20-(2(z+4z)-1)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

5z+1/4z-(2(+5z)-1)-20=0

We multiply all the terms by the denominator


5z*4z-((2(+5z)-1))*4z-20*4z+1=0

Wy multiply elements

20z^2-((2(+5z)-1))*4z-80z+1=0

We add all the numbers together, and all the variables

20z^2-80z-((2(+5z)-1))*4z+1=0

We move all terms containing z to the left, all other terms to the right

20z^2-80z-((2(+5z)-1))*4z=-1

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