5z+10=3(z-2)+6

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Solution for 5z+10=3(z-2)+6 equation: 



5z+10=3(z-2)+6

We move all terms to the left:

5z+10-(3(z-2)+6)=0



We calculate terms in parentheses: -(3(z-2)+6), so:

3(z-2)+6

We multiply parentheses

3z-6+6

We add all the numbers together, and all the variables

3z

Back to the equation:

-(3z)



We add all the numbers together, and all the variables

2z+10=0

We move all terms containing z to the left, all other terms to the right

2z=-10

z=-10/2

z=-5

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