5z+2(z-4)=13

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Solution for 5z+2(z-4)=13 equation: 



5z+2(z-4)=13

We move all terms to the left:

5z+2(z-4)-(13)=0

We multiply parentheses

5z+2z-8-13=0

We add all the numbers together, and all the variables

7z-21=0

We move all terms containing z to the left, all other terms to the right

7z=21

z=21/7

z=3

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