5z+2(z-5)=7(z-1)-1

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Solution for 5z+2(z-5)=7(z-1)-1 equation: 



5z+2(z-5)=7(z-1)-1

We move all terms to the left:

5z+2(z-5)-(7(z-1)-1)=0

We multiply parentheses

5z+2z-(7(z-1)-1)-10=0



We calculate terms in parentheses: -(7(z-1)-1), so:

7(z-1)-1

We multiply parentheses

7z-7-1

We add all the numbers together, and all the variables

7z-8

Back to the equation:

-(7z-8)



We add all the numbers together, and all the variables

7z-(7z-8)-10=0

We get rid of parentheses

7z-7z+8-10=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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