5z+4(4-z)=-(-z-4)+10

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Solution for 5z+4(4-z)=-(-z-4)+10 equation: 



5z+4(4-z)=-(-z-4)+10

We move all terms to the left:

5z+4(4-z)-(-(-z-4)+10)=0

We add all the numbers together, and all the variables

5z+4(-1z+4)-(-(-1z-4)+10)=0

We multiply parentheses

5z-4z-(-(-1z-4)+10)+16=0



We calculate terms in parentheses: -(-(-1z-4)+10), so:

-(-1z-4)+10

We get rid of parentheses

1z+4+10

We add all the numbers together, and all the variables

z+14

Back to the equation:

-(z+14)



We add all the numbers together, and all the variables

z-(z+14)+16=0

We get rid of parentheses

z-z-14+16=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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