5z+4(7+3z)=9z+12

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Solution for 5z+4(7+3z)=9z+12 equation: 



5z+4(7+3z)=9z+12

We move all terms to the left:

5z+4(7+3z)-(9z+12)=0

We add all the numbers together, and all the variables

5z+4(3z+7)-(9z+12)=0

We multiply parentheses

5z+12z-(9z+12)+28=0

We get rid of parentheses

5z+12z-9z-12+28=0

We add all the numbers together, and all the variables

8z+16=0

We move all terms containing z to the left, all other terms to the right

8z=-16

z=-16/8

z=-2

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