5z+42=4z+56

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Solution for 5z+42=4z+56 equation: 



5z+42=4z+56

We move all terms to the left:

5z+42-(4z+56)=0

We get rid of parentheses

5z-4z-56+42=0

We add all the numbers together, and all the variables

z-14=0

We move all terms containing z to the left, all other terms to the right

z=14

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