5z+9-4(z+12)=3(z-2)+13

Solution for 5z+9-4(z+12)=3(z-2)+13 equation:

5z+9-4(z+12)=3(z-2)+13

We move all terms to the left:

5z+9-4(z+12)-(3(z-2)+13)=0

We multiply parentheses

5z-4z-(3(z-2)+13)-48+9=0


We calculate terms in parentheses: -(3(z-2)+13), so:

3(z-2)+13

We multiply parentheses

3z-6+13

We add all the numbers together, and all the variables

3z+7

Back to the equation:

-(3z+7)


We add all the numbers together, and all the variables

z-(3z+7)-39=0

We get rid of parentheses

z-3z-7-39=0

We add all the numbers together, and all the variables

-2z-46=0

We move all terms containing z to the left, all other terms to the right

-2z=46

z=46/-2

z=-23