5z-4(7+3z)=9z+12

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Solution for 5z-4(7+3z)=9z+12 equation: 



5z-4(7+3z)=9z+12

We move all terms to the left:

5z-4(7+3z)-(9z+12)=0

We add all the numbers together, and all the variables

5z-4(3z+7)-(9z+12)=0

We multiply parentheses

5z-12z-(9z+12)-28=0

We get rid of parentheses

5z-12z-9z-12-28=0

We add all the numbers together, and all the variables

-16z-40=0

We move all terms containing z to the left, all other terms to the right

-16z=40

z=40/-16

z=-2+1/2

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