5z-4(z-9)=4+2z

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Solution for 5z-4(z-9)=4+2z equation: 



5z-4(z-9)=4+2z

We move all terms to the left:

5z-4(z-9)-(4+2z)=0

We add all the numbers together, and all the variables

5z-4(z-9)-(2z+4)=0

We multiply parentheses

5z-4z-(2z+4)+36=0

We get rid of parentheses

5z-4z-2z-4+36=0

We add all the numbers together, and all the variables

-1z+32=0

We move all terms containing z to the left, all other terms to the right

-z=-32

z=-32/-1

z=+32

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