5z-4=3(z+2)+2z

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Solution for 5z-4=3(z+2)+2z equation: 


Simplifying
5z + -4 = 3(z + 2) + 2z

Reorder the terms:
-4 + 5z = 3(z + 2) + 2z

Reorder the terms:
-4 + 5z = 3(2 + z) + 2z
-4 + 5z = (2 * 3 + z * 3) + 2z
-4 + 5z = (6 + 3z) + 2z

Combine like terms: 3z + 2z = 5z
-4 + 5z = 6 + 5z

Add '-5z' to each side of the equation.
-4 + 5z + -5z = 6 + 5z + -5z

Combine like terms: 5z + -5z = 0
-4 + 0 = 6 + 5z + -5z
-4 = 6 + 5z + -5z

Combine like terms: 5z + -5z = 0
-4 = 6 + 0
-4 = 6

Solving
-4 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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