5z-5(z+2)=2(z-2)-14

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Solution for 5z-5(z+2)=2(z-2)-14 equation: 



5z-5(z+2)=2(z-2)-14

We move all terms to the left:

5z-5(z+2)-(2(z-2)-14)=0

We multiply parentheses

5z-5z-(2(z-2)-14)-10=0



We calculate terms in parentheses: -(2(z-2)-14), so:

2(z-2)-14

We multiply parentheses

2z-4-14

We add all the numbers together, and all the variables

2z-18

Back to the equation:

-(2z-18)



We add all the numbers together, and all the variables

-(2z-18)-10=0

We get rid of parentheses

-2z+18-10=0

We add all the numbers together, and all the variables

-2z+8=0

We move all terms containing z to the left, all other terms to the right

-2z=-8

z=-8/-2

z=+4

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