5z2+7z+2=0

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Solution for 5z2+7z+2=0 equation: 



5z^2+7z+2=0

a = 5; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·5·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*5}=\frac{-10}{10}
=-1
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*5}=\frac{-4}{10}
=-2/5
$

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