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5z^2-17z+14=0
a = 5; b = -17; c = +14;
Δ = b2-4ac
Δ = -172-4·5·14
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-3}{2*5}=\frac{14}{10} =1+2/5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+3}{2*5}=\frac{20}{10} =2 $
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