5z2-500=0

Solution for 5z2-500=0 equation:

5z^2-500=0

a = 5; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·5·(-500)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*5}=\frac{-100}{10}
=-10
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*5}=\frac{100}{10}
=10
$