6(-1+2c)=5(2+2c)

Solution for 6(-1+2c)=5(2+2c) equation:

Simplifying
6(-1 + 2c) = 5(2 + 2c)
(-1 * 6 + 2c * 6) = 5(2 + 2c)
(-6 + 12c) = 5(2 + 2c)
-6 + 12c = (2 * 5 + 2c * 5)
-6 + 12c = (10 + 10c)

Solving
-6 + 12c = 10 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
-6 + 12c + -10c = 10 + 10c + -10c

Combine like terms: 12c + -10c = 2c
-6 + 2c = 10 + 10c + -10c

Combine like terms: 10c + -10c = 0
-6 + 2c = 10 + 0
-6 + 2c = 10

Add '6' to each side of the equation.
-6 + 6 + 2c = 10 + 6

Combine like terms: -6 + 6 = 0
0 + 2c = 10 + 6
2c = 10 + 6

Combine like terms: 10 + 6 = 16
2c = 16

Divide each side by '2'.
c = 8

Simplifying
c = 8